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原帖由 hww7 于 2007-11-25 14:45 发表 I suggest that: //a,b,c,d,e,f,are known,x,y are unknown; //d={d1,d2,d3,d4}are known; (a,b),(c,d),(e,f),(x,y) -------------------------------- sqrt((a-c)^2+(b-d)^2)=>D1 then match D1 with d ...